20r^2+8r^2=0

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Solution for 20r^2+8r^2=0 equation: 



20r^2+8r^2=0

We add all the numbers together, and all the variables

28r^2=0

a = 28; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·28·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{56}=0$

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